3.2 - 39 3.2 4 11 r0 hermetic jedec to-257aa high efficiency, soft recovery rectifier features ? small size ? ultra fast recovery ? soft recovery behavior ? extremely low losses at high switching speeds ? low i rm rating ? hermetic and isolated package ? available screened to mil-s-19500, tx, txv and s levels description this soft recovery, high speed rectifier is ideally suited for high performance in high voltage switching applications. the performance of this rectifier minimizes losses in power conversion and motor control circuits complementing the switching characteristics of power mosfets, igbts, and bipolar transistors. absolute maximum ratings t c = 25c peak inverse voltage .................................................. 800 & 1000 v maximum average d.c. output current @ t c = 100c ..........................12 a surge current (non-repetitve 8.3 nsec) ........................................70 a thermal resistance, junction-to-case ..................................... 2.0 c/w operating and storage temperature range ......................... -55c to +150c 12 amp, 800 & 1000 volts, 50 nsec trr om5010st OM5011ST .045 .035 .430 .410 .200 .190 .038 max. .120 typ. .537 .527 .665 .645 .420 .410 .150 .140 .750 .500 .200 typ. .045 .035 .005 cathode anode
3.2 205 craw ford street, leominster, ma 01453 usa (508) 534-5776 fax (508) 537-4246 om5010st - OM5011ST turn-off characteristics symbols test conditions min. typ. max. units t rr i f = 0.5 a; i r = 1 a; t j = 25c i f = 1 a; di/dt = -15 a/s; v r = 30 v; t j = 25c - - 50 ns i rm v r = 540 v; i f = 12 a - 6.5 7.2 a l .05 h; t j = 100c; di f /dt = -100 a/s electrical characteristics maximum maximum maximum type piv forward voltage reverse current reverse @ 12 a @ .8x piv recovery t j = 25 c t j = 150 c t j = 25 c t j = 125 c time om5010st 800 OM5011ST 1000 2.9 v 2.7 v 150 a 4 ma 50 definition of turn-off characteristics typical reverse current typical forward voltage i t t rr q rr t frm t f v i,v o i f i rm v r 0.25 - v rm 0.9 - i rm di f dt dt di f 100 50 30 20 10 5 2 1 1.8 2.0 2.2 2.4 3 t j = 125? t j = 25? i f = instantaneous forward current (amps) v f = instantaneous voltage (volts) 100 50 10 5 1 20 40 60 80 100 t j = 150? t j = 125? t j = 25? % of v rrm i r = reverse current, ma
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